#271 – Passing a Reference Type as an Output Parameter

You can pass a reference-typed variable to a method as an output parameter, using the out keyword.  This indicates that the parameter is an output method.  For a reference type, this means that the method is expected to change the reference to point to a different object.

        public static void FindBallPlayingDog(out Dog fav)
            fav = null;
            foreach (Dog d in AllDogs)
                if (d.Motto.Contains("ball"))
                    fav = d;

When calling the method, we need to include the out keyword as a parameter modifier:

            Dog kirby = new Dog("Kirby");
            kirby.Motto = "Love chasing balls";

            Dog jack = new Dog("Jack");
            jack.Motto = "Sneak away when possible";

            Dog fav = jack;

            Dog.FindBallPlayingDog(out fav);   // Fav is now Kirby

About Sean
Software developer in the Twin Cities area, passionate about .NET technologies. Equally passionate about my own personal projects related to family history and preservation of family stories and photos.

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