#1,031 – Requiring Generic Type Parameters to Implement an Interface

By default, when you specify a type parameter in a generic class, the type can be any .NET type.  There are times, however, when you’d like to constrain the type in some ways, allowing only types that implement a particular interface.

You can constrain a type parameter to be of a type that implements a particular interface, using the where keyword.  In the example below, the PileOf class has a type parameter that must be a type that implements the IBark interface.  (The EverybodyBark method calls a method in IBark).

    public class PileOf<T> where T : IBark
    {
        private List<T> thePile;

        public PileOf()
        {
            thePile = new List<T>();
        }

        public void AddThing(T thing)
        {
            thePile.Add(thing);
        }

        public void EverybodyBark()
        {
            foreach (T creature in thePile)
            {
                creature.Bark();
            }
        }
    }

We can now create a PileOf<Dog>, because Dog implements IBark, but we can’t create a PileOf<Cow>.

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About Sean
Software developer in the Twin Cities area, passionate about software development and sailing.

2 Responses to #1,031 – Requiring Generic Type Parameters to Implement an Interface

  1. Pingback: Dew Drop – February 12, 2014 (#1721) | Morning Dew

  2. Pingback: #1,035 – Summary of Type Parameter Constraints | 2,000 Things You Should Know About C#

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